MyQuestionIcon

12

You visited us 12 times! Enjoying our articles? Unlock Full Access!

Carnot Cycle

The temperatu...

Question

The temperature of reservoir of Carnot's engine operating with an efficiency of 70% is 1000K. The temperature of its sink is

A

300 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

400 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

500 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

700 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
300 K

$η = 1 - \frac{T_{2}}{T_{1}} \Rightarrow \frac{70}{100} = 1 - \frac{T_{2}}{1000} \Rightarrow T_{2} = 300 K$

Suggest Corrections

thumbs-up

15

Similar questions

Q. The temperature of the reservoir of Carnot’s engine operating with an efficiency of

70

1000 K

. The temperature of the source is?

Q. The efficiency of carnot's engine is 50%. The temperature of its sink is

7^{o} C

. To increase its efficience 70%. What is the increase in temperature of the source ?

Q. A Carnot's engine operates with an efficiency of 40% with its sink at

27 ° C

. The amount by which the temperature of the source be increased with an aim to increase the efficiency by 10% is K.

Q. A Carnot's engine has an efficiency of

50

% at sink temperature

50^{\circ}

. Calculate the temperature of source :

Q. The efficiency of a Carnot engine operating with reservoir temperature of

100^{o} C

- 23^{o}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Carnot Cycle

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon