The temperature on Celsius scale whose numerical value is half that of the absolute reading

273^{\circ} C

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546^{\circ} C

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0^{\circ} C

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27^{\circ} C

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Solution

The correct option is C $273^{\circ} C$
$C + 273 = K$
$⟹ C + 273 = 2 C$
$C = 273^{o} C$

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Similar questions

- 273^{0} C

30^{0} C

{- 100}^{0} C

{- 40}^{0} C

Change the following celsius temperature to kelvin scale.

(i) – 273°C
(ii) – 100°C
(iii) – 40°C
(iv) + 30°C

The temperature on the Kelvin scale reads 40 K. What will be the value on the Celsius scale?

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