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Standard XII

Physics

Convection

The temperatu...

Question

The temperature variation under steady heat conduction across a composite slab of two materials with thermal conductivities $K_{1}$ and $K_{2}$ is shown in figure. Then, which one of the following statements holds?

K_{1} > K_{2}

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K_{1} < K_{2}

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K_{1} = K_{2}

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K_{1} = 0

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Solution

The correct option is B $K_{1} < K_{2}$
Heat = $K A \frac{δ T}{δ x}$
The same amount of heat transfers from both the slabs.
From figure we can see that
$\frac{δ T_{1}}{δ x} > \frac{δ T_{2}}{δ x}$
$\frac{H}{K_{1} A} > \frac{H}{K_{2} A}$
$⟹ K_{1} < K_{2}$

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The temperature variation under steady heat conduction across a composite slab of two materials with thermal conductivities K1 and K2 is shown in figure. Then, which one of the following statements holds?

The correct option is B K1<K2Heat =KAδTδxThe same amount of heat transfers from both the slabs.From figure we can see thatδT1δx>δT2δx HK1A>HK2A⟹K1<K2

The temperature variation under steady heat conduction across a composite slab of two materials with thermal conductivities $K_{1}$ and $K_{2}$ is shown in figure. Then, which one of the following statements holds?

The correct option is B $K_{1} < K_{2}$
Heat = $K A \frac{δ T}{δ x}$
The same amount of heat transfers from both the slabs.
From figure we can see that
$\frac{δ T_{1}}{δ x} > \frac{δ T_{2}}{δ x}$
$\frac{H}{K_{1} A} > \frac{H}{K_{2} A}$
$⟹ K_{1} < K_{2}$