The temperatures of two bodies A and B are 727- C and 127- C- The ratio of rate of emission of radiations will beA- 727 - 127B- 625 - 16C- 1000 - 400D- 100 - 16

The correct option is B 625/16 E_1/E_2=(T_1/T_2)^4=(727+273/127+273)^4=(1000)^4/(400)^4=10^4/4^4=625/16 ...

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Standard XII

Physics

Wave Equation of EM Waves

The temperatu...

Question

The temperatures of two bodies A and B are $727^{o} C$ and $127^{o} C$ . The ratio of rate of emission of radiations will be

727/127

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625/16

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1000/400

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100/16

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Solution

The correct option is B
625/16

$\frac{E_{1}}{E_{2}} = (\frac{T_{1}}{T_{2}})^{4} = (\frac{727 + 273}{127 + 273})^{4} = \frac{(1000)^{4}}{(400)^{4}} = \frac{10^{4}}{4^{4}} = \frac{625}{16}$

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