The temperatures of two bodies measured by a thermometer are t1=20∘C±0.5∘C and t2=50∘C±0.5∘C. The temperature difference and the error therein is:
A
30∘C±1∘C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
70∘C±0.5∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
30∘C±0.5∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
70∘C±1∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A30∘C±1∘C Here, t1=20∘C±0.5∘C t2=50∘C±0.5∘C The temperature difference of two bodies is t=t2−t1=50∘C−20∘C=30∘C The error in temperature difference is given by Δt=(Δt1+Δt2) =(0.5∘C+0.5∘C)=1∘C ∴The temperature difference is 30∘C±1∘C.