The correct option is B Ca(OH)2
The temporary hardness of water due to calcium bicarbonate can be removed by adding Ca(OH)2. The calcium salt is precipitated out as CaCO3.
Temporary hardness of water is due to the presence of bicarbonates of calcium and magnesium.
Ca(HCO3)2+Ca(OH)2→2CaCO3+2H2O
The temporary hardness of water can be removed by the addition of calculated quantity of milk of lime which converts soluble bicarbonates into insoluble carbonates which can be removed.
Hence, option B is correct.