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Standard XII

Physics

Introduction to Radial & Tangential Acceleration

The tension i...

Question

The tension in the string revolving in a vertical circle with a mass m at the end which is at the lowest position

\frac{m v^{2}}{r}

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\frac{m v^{2}}{r} - m g

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\frac{m v^{2}}{r} + m g

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m g

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Solution

The correct option is C $\frac{m v^{2}}{r} + m g$
R.E.F image
$F_{c}$ Fore of centrifygal
$T = F_{c} + m g$
$= \frac{m v^{2}}{12} + m g$
so, option (c)

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The tension in the string revolving in a vertical circle with a mass m at the end which is at the lowest position

The correct option is C mv2r+mgR.E.F image Fc Fore of centrifygal T=Fc+mg=mv212+mgso, option (c)

The correct option is C $\frac{m v^{2}}{r} + m g$
R.E.F image
$F_{c}$ Fore of centrifygal
$T = F_{c} + m g$
$= \frac{m v^{2}}{12} + m g$
so, option (c)