The tension (T) in the string is (Assume pulley and strings are light and smooth. Take g as acceleration due to gravity)
A
m1g
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B
m2g
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C
∑F=ma
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D
(m1+m2)g
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Solution
The correct option is D(m1+m2)g Let the blocks of mass m1 and m2 and the string in between the blocks act as a system.
Since the system is in equilibrium and the string is massless, using equilibrium condition: T–(m1+m2)g=0 T=(m1+m2)g