The tension (T) in the string is (Assume pulley and strings are light and smooth. Take g as acceleration due to gravity)

(m_{1} + m_{2}) g

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m_{2} g

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\sum F = m a

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m_{1} g

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Solution

The correct option is A $(m_{1} + m_{2}) g$
Let the blocks of mass $m_{1}$ and $m_{2}$ and the string in between the blocks act as a system.
Since the system is in equilibrium and the string is massless, using equilibrium condition:
$T - (m_{1} + m_{2}) g = 0$
$T = (m_{1} + m_{2}) g$

Hence, the correct answer is option (4).

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The tension (T) in the string is (Assume pulley and strings are light and smooth. Take g as acceleration due to gravity)

The correct option is A (m1+m2)gLet the blocks of mass m1 and m2 and the string in between the blocks act as a system. Since the system is in equilibrium and the string is massless, using equilibrium condition: T–(m1+m2)g=0 T=(m1+m2)g Hence, the correct answer is option (4).