The correct option is A Zero
The forces on the block will have component of its own weight down the incline plane and friction up the incline plane.
mgsinθ=10(10)sin30∘=50 N
Frictional force =μmgcosθ=(0.7)(10)(10)√32=35√3 N>50 N
Frictional force is sufficient to oppose the cause of motion.
Hence, tension will be zero.