Question

The tension T in the string shown in the figure is

• A. $Zero$
• B. $50N$
• C. $35\sqrt{3}N$
• D. $(\sqrt{3}-1)50N$

Answer 1

The correct option is A $Zero$

Formula,

$f_{max}=\mu mg\cos {30}^{\circ }$

$=0.7\times 10\times 10\times \frac{\sqrt{3}}{2}=60.62N$

$mg\sin {30}^{\circ }=10\times 10\times \frac{1}{2}=50N$

$f=50N$ and friction $f_{max}=60.62N$

Tension will be 0