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B
m+nCn
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C
m+nCm−n
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D
None of these
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Solution
The correct option is Cm+nCn (1+x)m(1+1x)n =(1+x)nxn.(1+x)m =(1+x)m+nxn Writing the general expression for any term in the above expansion. Tr+1=m+nCrxr.x−n =m+nCrxr−n For term independent of x r−n=0 r=n Hence the term is Tn+1 and the coefficient is =m+nCn