The term independent of x in the expansion of 1-x2X-1-x10A- None of theseB- 11 C5C- 10 C5D- 10 C4

The correct option is B Experiession=1/x^10(1 2x+x^2)(1+x^2)^10 =1/x^10(1+x^2)^10 2/x^9(1+x^2)^10+1/x^8(1+x^2)^10 ∴ The term indcepend of x ^10C_5 2×0+^10C_4 ...

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Byju's Answer

Standard XI

Mathematics

Term Independent of X

The term inde...

Question

The term independent of x in the expansion of $(1 - x)^{2} {(X + \frac{1}{x})}^{10}$ is

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Solution

The correct option is A
$E x p e r i e s s i o n = \frac{1}{x^{10}} (1 - 2 x + x^{2}) (1 + x^{2})^{10} = \frac{1}{x^{1} 0} (1 + x^{2})^{10} - \frac{2}{x^{9}} (1 + x^{2})^{10} + \frac{1}{x^{8}} (1 + x^{2})^{10} ∴ T h e t e r m i n d c e p e n d o f x^{1} 0 C_{5} - 2 \times 0 +^{10} C_{4} =^{11} C_{5}$

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The correct option is A Experiession=1x10(1−2x+x2)(1+x2)10=1x10(1+x2)10−2x9(1+x2)10+1x8(1+x2)10∴Thetermindcependofx10C5−2×0+10C4=11C5

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