The correct option is C 1754
Given, (1+x+2x3)(3x22−13)9
=[(3x22−13x)9]+x(3x22−13x)9+[2x3(3x22−13x)9]
Therefore for (3x22−13)9
Tr+1=(−1)r9Cr39−2r2r−9x18−3r
Therefore only terms indicated by the square bracket have independent term because the term not having a square bracket has an independent term for r=193 which is not possible.
Therefore, the independent terms are T7 in first term and T8 in last term.
Therefore sum of the coefficients of the independent terms is
=9C63−32−3−29C73−52−2
=8427(8)−2(36)243(4)
=1754