The term independent of x in the expansion of (1+x+2x3)(3x22−13x)9 is
In(3x22−13x)9, Tr+1=9Cr(3x22)9−r(−13x)r=9Cr39−2r(−1)rx18−2r−r29−r
18–2r–r=0⇒18–3r=0⇒r=6
18–2r–r=⇒18–3r=0⇒r=6
18 – 2r – r = 18 – 3r = – 1 ⇒ has no integral value.
18–2r–r=–3⇒18–3r=–3⇒3r–21⇒r=7
Required term =9C63−3(−1)623+2.9C7(−1)73−522=8427×8−2×36243×4=718−227=1754