The term independent of x in the expansion of (1+x)n(1+1x)n,is
A
C02+2C12+3.C22+...(n+1)Cn2
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B
(C0+C1+...+Cn)2
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C
C02+C12+...+Cn2
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D
none of these
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Solution
The correct option is DC02+C12+...+Cn2 (1+x)n(1+1x)n =(1x)n(1+x)2n The coefficient of xn in (1+x)2n implies Tn+1=2nCnxn Hence the term independent of x will be Tn+1 and its coefficient will be 2nCn