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Question

The term independent of x in the expansion of (x+1x23x13+1x1xx12)10 is



A

-252

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B

-210

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C

210

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D

None

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Solution

The correct option is C

210


x+1x23x13+1x1x12(x121)10

= (x13+1)(1+x12)

Tr+1 in

(x13x12)10 = 10Cr(x13)10r(1)r.(x12)r

= (1)r10Crx(205r)6

For coeff. of x0,5r = 20 r = 4

Hence, term independent of x = (1)4.10C4=210.


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