The term independent of x in the expansion of (x+1x23−x13+1−x−1x12+1)10 is
210
x+1x23−x13+1−x−1x12−(x12−1)10
= (x13+1)−(1+x−12)
∴ Tr+1 in (x13−x12)10 = 10Cr(x13)10r(−1)r.(x12)r
= (−1)r10Crx(20−5r)6
For coefficient of x0,5r = 20 ⇒ r = 4
Hence, term independent of x = (−1)4.10C4=210.