The term that corrects for the attractive forces present in a real gas in the Vander Waals' equation is:

- n b

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\frac{a n^{2}}{V^{2}}

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- \frac{a n^{2}}{V^{2}}

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n b

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Solution

The correct option is B $\frac{a n^{2}}{V^{2}}$
Loss in pressure is $\frac{n^{2} a}{V^{2}}$ due to attraction forces in real gas.

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Similar questions

a

(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T

(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T

(p + \frac{a n}{V^{2}}) (V - n b) = n R T,

\frac{a n}{V^{2}}

n b

V_{1}

V_{2}

(V - β n) (P + \frac{a n^{2}}{V}) = n R T

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