The term that is independent of x, in the expansion of (32x2−13x)9 is
A
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B
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C
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D
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Solution
The correct option is B (3xx2−13x)9=∑9r=09Cr(32x2)9−r(−13x)rForthetermthatisindependentofx,wemusthave,18−2r−r=0⇒r=6Thus,requiredterm=9C6(32x2)3(−13x)6i.e,9C6(32)3(13)6