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Question

The term that is independent of x, in the expansion of (32x213x)9 is


Solution

The correct option is C
(3xx213x)9=9r=0 9Cr(32x2)9r(13x)rFor the term that is independent of x, we must have,182rr=0r=6Thus, required term=9C6(32x2)3(13x)6i.e, 9C6(32)3 (13)6

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