Question

The terminal velocity $V$ of a spherical ball of lead of radius $R$ falling through a viscous liquid varies with $R$ such that:

• A. $\frac{V}{R}=$Constant
• B. $VR=$ Constant
• C. $V=$ Constant
• D. $\frac{V}{R^2}=$Constant

Answer 1

The correct option is D $\frac{V}{R^2}=$Constant

$v=\frac{2R^2(\sigma -\lambda )g}{9\eta }\lfloor \because fromformulaforterminalvelocity\rfloor$

$\frac{v}{R^2}=\frac{2(\sigma -\lambda )g}{9\eta }=K\left(constant\right)$