The test scores of two students are given. The mean of student 1 is the mean of student 2.

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Solution

The correct option is A <
The given data is

Mean of test scores of student 1 = $\frac{s u m o f a l l d a t a}{n u m b e r o f d a t a g i v e n}$

Sum of all data = 45 + 56 + 48 + 64 + 72 + 84 + 62 + 77

= 508

Number of data given = 8

Mean of test scores of student 1 = $\frac{508}{8}$

= 63.5

Mean of test scores of student 2 = $\frac{s u m o f a l l d a t a}{n u m b e r o f d a t a g i v e n}$

Sum of all data = 48 + 58 + 67 + 81 + 76 + 82 + 62 + 78
= 552

Number of data given = 8

Mean of test scores of student 2 = $\frac{552}{8}$
= 69

Hence, the mean of test scores of student 1 is less than the mean of test scores of student 2.

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