Given,
pKa(CH3COOH)=4.76 and pKb(NH4OH)=4.75
Step 1: Salt type
Ammonium acetate (CH3COONH4) is a salt of weak acid, acetic acid (CH3COOH) and weak base, ammonium hydroxide (NH4OH).
The reaction taking place is:
CH3COOH+NH4OH⇌CH3COONH4+H2O
Step 2: Formula of pH
For salt of weak acid and weak base, the pH of salt in solution is given as:
pH=7+12[pKa–pKb]
Step 3: pH value
So,
pH=7+12[4.76–4.75]=7+12[0.01]=7+0.005=7.005
Final answer:
7.005