The the system in the figure is in equilibrium. The value of PR in terms of RQ is equal to

\frac{1}{4} R Q

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\frac{3}{8} R Q

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\frac{3}{5} R Q

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\frac{2}{5} R Q

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Solution

The correct option is C $\frac{3}{5} R Q$
By taking moment of forces about point R, $5 \times P R - 3 \times R Q = 0 \Rightarrow P R = \frac{3}{5} R Q .$

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P S ⊥ s e g R Q s e g Q T ⊥ s e g P R

R Q = 6, P S = 6

P R = 12

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In adjoining figure, $P S ⊥ R Q$ and $Q T ⊥ P R$ . If $R Q = 6, P S = 6$ and $P R = 12$ , then Find $Q T$ .

In the figure: PQ = 10 cm, QS = 6 cm and RQ = 9 cm.
The length of side PR is.

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