Question

The theoretical capacity (vehicle/hr) of a traffic lane with one way traffic flow at a stream speed of 40 kmph will be _____ if it is given that average space gap between vehicles follow the relation $S_g=0.278Vt$ where V is the stream speed in kmph and, t is the average reaction time of 0.7 sec and average length of vehicle is 6 m

Answer 1

$Given,V=40kmph,t=0.7sec,L=6m$

Average spacing is given by
$S=0.278\times 40\times 0.7=7.78m$
$\therefore \text{Average}c/c\text{spacing}=7.78+6=13.78m$
$\therefore \text{Density of vehicles}=\frac{1000}{13.78}=72.569\left(vehicle/km\right)$
$\therefore \text{Theoretical capacity}\left(q\right)=kv$
$=72.569\times 40$
$=2902.76\approx 2903vehicle/hr$