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Standard XII

Chemistry

Heat Capacity

the thermal c...

Question

the thermal capacity of 40 g of aluminium $(s p e c i f i c h e a t = \frac{0.2 c a l}{g m \times C})$ is

40cal/

C

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160cal/

C

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200cal/

C

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8cal/

C

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Solution

The correct option is D 8cal/ $C$
Given:
mass, $m = 40 g$ , specific heat, $C = 0.2 c a l g^{- 1} ° C^{- 1}$
We know,
Thermal capacity $= m \times C = 40 \times 0.2 = 8 c a l ° C^{- 1}$

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the thermal capacity of 40 g of aluminium (specificheat=0.2calgm×C) is

The correct option is D 8cal/CGiven:mass, m=40g, specific heat, C=0.2calg−1°C−1We know, Thermal capacity =m×C=40×0.2=8cal°C−1

the thermal capacity of 40 g of aluminium $(s p e c i f i c h e a t = \frac{0.2 c a l}{g m \times C})$ is

The correct option is D 8cal/ $C$
Given:
mass, $m = 40 g$ , specific heat, $C = 0.2 c a l g^{- 1} ° C^{- 1}$
We know,
Thermal capacity $= m \times C = 40 \times 0.2 = 8 c a l ° C^{- 1}$