CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The thermal conductance (reciprocal of the thermal resistance) for axial flow of a truncated cone of length l is πK(r1r2)ln2. If the radius at the two ends of the cone are r1 and r2 and thermal conductivity of the material is K, then the value of n2 is



Open in App
Solution




Thermal resistance is given by R=lKA
For the disc element, as shown in figure
dR=dxKπr2
From the diagram,
tan α=rr1x=r2r1l
x=l(r2r1)×(rr1)
dx=lr2r1dr
Therefore,
dR=lKπ(r2r1)drr2
Integrating
R0dR=lKπ(r2r1)r2r1drr2
R=lπk(r2r1)[1r]r2r1
R=lπK(r2r1)[1r11r2]
R=lπKr1r2
or
1R=πKr1r2l
n2=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factors Affecting Resistance & How They Affect_Tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon