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Question

The thermal conductance (reciprocal of the thermal resistance) for axial flow of a truncated cone of length l is πK(r1r2)ln2. If the radius at the two ends of the cone are r1 and r2 and thermal conductivity of the material is K, then the value of n2 is



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Solution




Thermal resistance is given by R=lKA
For the disc element, as shown in figure
dR=dxKπr2
From the diagram,
tan α=rr1x=r2r1l
x=l(r2r1)×(rr1)
dx=lr2r1dr
Therefore,
dR=lKπ(r2r1)drr2
Integrating
R0dR=lKπ(r2r1)r2r1drr2
R=lπk(r2r1)[1r]r2r1
R=lπK(r2r1)[1r11r2]
R=lπKr1r2
or
1R=πKr1r2l
n2=1

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