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Standard XII

Physics

Thermal Expansion

The thermal c...

Question

The thermal conductivity of a material in CGS system is 0.4. In steady state, the rate of flow of heat 10 cal/sec- $c m^{2}$ , then the thermal gradient will be

10° C / cm

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12° C / cm

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25° C / cm

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20° C / cm

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Solution

The correct option is C
25° C / cm

$\frac{△ Q}{△ t} = \frac{K A △ θ}{△ x} \Rightarrow T h e r m a l g r a d i e n t \frac{△ θ}{△ x}$

$= \frac{(\frac{△ Q}{△ r})}{K A} = \frac{10}{0.4} = 25^{\circ} C / c m$

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The thermal conductivity of a material in CGS system is 0.4. In steady state, the rate of flow of heat 10 cal/sec-cm2, then the thermal gradient will be

The correct option is C 25° C / cm △Q△t=KA△θ△x⇒Thermal gradient△θ△x =(△Q△r)KA=100.4=25∘C/cm

The thermal conductivity of a material in CGS system is 0.4. In steady state, the rate of flow of heat 10 cal/sec- $c m^{2}$ , then the thermal gradient will be

The correct option is C
25° C / cm

$\frac{△ Q}{△ t} = \frac{K A △ θ}{△ x} \Rightarrow T h e r m a l g r a d i e n t \frac{△ θ}{△ x}$

$= \frac{(\frac{△ Q}{△ r})}{K A} = \frac{10}{0.4} = 25^{\circ} C / c m$