Question

The thickness of a metallic sheet is reduced from an initial value of 16 mm to a final value of 10mm in one single pass rolling with a pair of cylindrical rollers each of diameter of 400mm The bite angle in degree will be

• A. 5.936
• B. 7.936
• C. 8.936
• D. 9.936

Answer 1

The correct option is D 9.936

$\text{Initial sheet thickness,}{t}_1=16mm$

$\text{Final sheet thickness,}{t}_2=10mm$

$\text{Roll radius,}R=\frac{400}{2}=200mm$

$tan\alpha$ = $\sqrt{\frac{t_1-t_2}{R}}=\sqrt{\frac{16-10}{200}}$

$tan\alpha$ = 0.173

$\therefore \text{Bite angle,}\alpha =ta{n}^{-1}\left(0.173\right)={9.936}^{\circ }$