Question

The thickness of the blank needed to produce, by power spinning a missile cone of thickness $1.5$ mm and half cone angle ${30}^o$

• A. $3.0$ mm
• B. $2.5$ mm
• C. $2.0$ mm
• D. $1.5$ mm

Answer 1

The correct option is A $3.0$ mm

$\text{Thickness of blank}=\frac{\text{cone thickness}}{cos\left(2\alpha \right)}=\frac{1.5}{cos{60}^o}=3.0\text{mm}$