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Question

The thimble of a screw gauge has 100divisions. The spindle advances2mm when the screw is turned through four revolutions. What is the least count of the screw gauge?


A

0.0005cm

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B

0.005cm

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C

0.050m

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D

0.050mm

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Solution

The correct option is A

0.0005cm


Step 1: Given data and formula used

Pitch=(movingdistancebyascrewx)(numberofrotationsn)=2mm4=0.5mm

Pitch(P) = 0.5 mm

Number of head scale division(N) = 50

(L.C)stands for least count

L.C=PN

Step 2: Calculation of least count

L.C=PN=0.5100=0.005mm=0.0005cm

Hence, the correct option is (a).


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