Question

The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned two revolutions.

(i) What is the pitch of screw gauge ?

(ii) What is the least count of the screw gauge ?

Answer 1

No. of divisions on the circular scale = 50
(i) Pitch = Distance moved ahead in one revolution
= 1 mm/2 = 0.5 mm

(ii) L.C. = Pitch/No. of divisions on the circular head
= (0.5/50) mm
= 0.01 mm