The third term from the end in the expansion of 3 x-5-5-2 x8 is

The correct option is D 3^rd term from the end = 7^th term from the beginning =( 1)^6 ^8C_6 ( 3x/5 )^2 ( 5/2x )^6=^8C_2 3^2 x^2/5^2. 5^6/2^6 x^6=8 × 7/2×3^2 × ...

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Standard XII

Mathematics

Binomial Expression

The third ter...

Question

The third term from the end in the expansion of ${(\frac{3 x}{5} - \frac{5}{2 x})}^{8}$ is

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Solution

The correct option is D

$3^{r d}$ term from the end = $7^{t h}$ term from the beginning

$= (- 1)^{6}^{8} C_{6} {(\frac{3 x}{5})}^{2} {(\frac{5}{2 x})}^{6} =^{8} C_{2} \frac{3^{2} x^{2}}{5^{2}} . \frac{5^{6}}{2^{6} x^{6}} = \frac{8 \times 7}{2} \times \frac{3^{2} \times 5^{4}}{2^{6}} \times \frac{1}{x^{4}} = \frac{7 \times 9 \times 625}{16 x^{4}} = \frac{39375}{16 x^{4}}$

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The third term from the end in the expansion of (3x5−52x)8 is

The correct option is D 3rd term from the end = 7th term from the beginning =(−1)6 8C6(3x5)2(52x)6=8C232x252.5626x6=8×72×32×5426×1x4=7×9×62516x4=3937516x4

The third term from the end in the expansion of ${(\frac{3 x}{5} - \frac{5}{2 x})}^{8}$ is