The third term in the expansion of 1x - xlog10x5 is 1000 then x-

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Exponents with like Bases

The third ter...

Question

The third term in the expansion of ${(\frac{1}{x} + x {log}_{10} x)}^{5}$ is $1000$ then $x$ =

1

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10

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10^{2}

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10^{3}

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Similar questions

If the third term in the expansion of ${(\frac{1}{x} + x^{l o g} 10^{x})}^{5}$ is 1000, then x =

(\frac{1}{x} + x^{{log}_{10} x})^{5}

1, 000

x

x

{(x + x^{l o g_{10} x})}^{5}

10, 00, 000

(x + x^{l o g_{10} x})^{5}

10^{6}

x

{[(1 / x) + x^{{log}_{10} x}]}^{5}

1000

x

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