Question

The third term of a G.P. is $9$. The product of its first five terms is

• A. $3^{10}$
• B. $3^5$
• C. $3^{12}$
• D. $3^9$

Answer 1

The correct option is A $3^{10}$

Let, the first five terms of G.P. are:$\frac{a}{r^2},\frac{a}{r},a,ar,a{r}^2$.
Given, third term, $a=9$
The product of first five terms $=\frac{a}{r^2}\times \frac{a}{r}\times a\times ar\times a{r}^2=a^5=9^5=3^{10}$