Question

The third term of a geometric progression is $4$. The product of the first five terms is

• A. $4^3$
• B. $4^4$
• C. $4^5$
• D. $4^6$

Answer 1

The correct option is C $4^5$

Let $a$ and $r$ the first term and common ratio, respectively.

Given:Third term$=a{r}^2=4$

Product of first $5$ terms is

$=a.ar.a{r}^2.a{r}^3.a{r}^4$

$=a^5{r}^{10}$

$={\left(a{r}^2\right)}^5$

$=4^5$