The third term of an A.P. is 7 and its 7th term is 2 more than thrice of its 3rd term. Find the common difference .
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Solution
The third term of an A.P. is a+2d where a is the first term and d, the common difference. So, a+2d=7 The next given condition says a+6d=21+2=23 Solving simultaneously, we have 4d=23−7=16 ⇒d=4.