Question

The third virial coefficient of a $He$ gas is $4\times {10}^{-2}$ $(lit/mol{)}^2$, then what will be volume of 2 mole $He$ gas at 1 atm $273K$ $(273K>T_B)$?

• A. $22.0lit$
• B. $44.0lit$
• C. $44.8lit$
• D. $45.3lit$

Answer 1

The correct option is D $45.3lit$

$4\times {10}^{-2}=b^2$

$b=2\times {10}^{-1}$

$p(v-nb)=nRT$

$1(v-2(0.2\left)\right)=2\left(0.0821\right)\times 273$

$v=45.3$ lit.