The three exterior angles of a triangle are $130^{o}, 140^{o}, x^{o}$ then $x^{o}$ is:

90^{o}

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100^{o}

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110^{o}

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120^{o}

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Solution

The correct option is A $90^{o}$
The sum of the exterior angles of a triangle is 360 degree.
$130 + 140 + x^{o} = 360$
$\Rightarrow x^{o} = 360 - 140 - 130$
$\Rightarrow x^{o} = 360 - 270 = 90^{o}$

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