Question

The three initial and final positions of a man on the x-axis are given as
(i) (-3 m, 7 m) (ii) (7 m, -3 m)
(iii) (-7 m, 3 m)
Which pair gives the negative displcement?

• A. (i)
• B. (ii)
• C. (iii)
• D. (i) and (iii)

Answer 1

The correct option is B (ii)

Displacement = Final position - Initial position

$\Delta x=x_2-x_1$

Then,

$\left(i\right)\Delta x=7m-(-m)=10m$

$\left(ii\right)\Delta x=-3m-7m=-10m$

$\left(iii\right)\Delta x=3m-(-7m)=10m$

Option (b)