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The three roo...

Question

The three roots of the equation $f (x) = 0$ are $x = - 2, 0, 3$ . What are the three value of $x$ for which $f (x - 3) = 0$ ?

- 5, - 3, 0

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- 2, 0, 3

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0, 6, 8

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1, 3, 6

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Solution

The correct option is D $1, 3, 6$
Root of $f (x) = 0$ are $- 2, 0, 3$ so
$f (x) = (x + 1) (x) (x - 3)$
Now, $f (x - 3) = (x - 1) (x - 3) (x - 6)$
Hence, $f (x - 3) = 0 \Rightarrow x = 1, 3, 6$

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The three roots of the equation f(x)=0 are x=−2,0,3. What are the three value of x for which f(x−3)=0?

The correct option is D 1,3,6Root of f(x)=0 are −2,0,3 so f(x)=(x+1)(x)(x−3) Now, f(x−3)=(x−1)(x−3)(x−6) Hence, f(x−3)=0⇒x=1,3,6

The three roots of the equation $f (x) = 0$ are $x = - 2, 0, 3$ . What are the three value of $x$ for which $f (x - 3) = 0$ ?

The correct option is D $1, 3, 6$
Root of $f (x) = 0$ are $- 2, 0, 3$ so
$f (x) = (x + 1) (x) (x - 3)$
Now, $f (x - 3) = (x - 1) (x - 3) (x - 6)$
Hence, $f (x - 3) = 0 \Rightarrow x = 1, 3, 6$