The three sides of a triangle are consecutive integers and their perimeter is $72 c m$ . Find the measure of each side of the triangle.

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Solution

Perimeter of triangle $= 72 c m$
Let the sides of triangle be : $n, n + 1, n + 2$
$∴$ According to Question
$(n) + (n + 1) + (n + 2) = 72$
$3 n + 3 = 72$
$3 n = 69, n = 23$
Side of triangle are $(23, 24, 25) c m$

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The three sides of a triangle are consecutive integers and their perimeter is 72 cm. Find the measure of each side of the triangle.

Perimeter of triangle =72 cmLet the sides of triangle be : n,n+1,n+2∴ According to Question(n)+(n+1)+(n+2)=723n+3=723n=69, n=23Side of triangle are (23, 24, 25) cm

The three sides of a triangle are consecutive integers and their perimeter is $72 c m$ . Find the measure of each side of the triangle.

Perimeter of triangle $= 72 c m$
Let the sides of triangle be : $n, n + 1, n + 2$
$∴$ According to Question
$(n) + (n + 1) + (n + 2) = 72$
$3 n + 3 = 72$
$3 n = 69, n = 23$
Side of triangle are $(23, 24, 25) c m$