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Question

The three straight lines ax+by=c,bx+cy=a and cx+ay=b are collinear, if.

A
b+c=a
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B
c+a=b
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C
a+b+c=0
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D
a+b=c
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Solution

The correct option is C a+b+c=0
Given lines are
ax+by=c,
bx+cy=a,
cx+ay=b
On adding these three lines, we get
ax+by+bx+cy+cx+ay=a+b+c
(a+b+c)x+(a+b+c)y=a+b+c
For collinearity, 0x+0y=0
On comparing, we get
a+b+c=0

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