The three straight lines ax+by=c,bx+cy=a and cx+ay=b are collinear, if.
A
b+c=a
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B
c+a=b
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C
a+b+c=0
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D
a+b=c
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Solution
The correct option is Ca+b+c=0 Given lines are ax+by=c, bx+cy=a, cx+ay=b On adding these three lines, we get ax+by+bx+cy+cx+ay=a+b+c ⇒(a+b+c)x+(a+b+c)y=a+b+c For collinearity, 0x+0y=0 On comparing, we get a+b+c=0