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Question

The three vertices of a parallelogram are (3, 4), (3, 8) and (9, 8). Find the fourth vertex.

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Solution

Consider A(3, 4), B (3, 8) and C(9, 8).

Let D (x, y) be the fourth vertex of the parallelogram ABCD.

Midpoint of AC = left square bracket fraction numerator left parenthesis space 3 plus space 9 space right parenthesis over denominator 2 end fraction comma space fraction numerator left parenthesis 4 space plus space 8 right parenthesis over denominator 2 end fraction right square bracket= (6,6)

Midpoint of BD =left square bracket fraction numerator left parenthesis space x space plus space 3 space right parenthesis over denominator 2 end fraction space comma space fraction numerator left parenthesis y space plus space 8 right parenthesis over denominator 2 end fraction right square bracket

Since, the diagonals of parallelogram bisect each other at O.

∴ Mid point of BD = Mid point of AC

left square bracket fraction numerator left parenthesis space x space plus space 3 space right parenthesis over denominator 2 end fraction space comma space fraction numerator left parenthesis y space plus space 8 right parenthesis over denominator 2 end fraction right square bracket = (6,6)

x + 3 = 12 and y + 8 = 12

x = 9 and y = 4
∴ (9, 4) is the fourth vertex.

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