The threshold energy of the reaction is when PE of B is 30kJmol−1.
A
130
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B
140
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C
123
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D
125
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Solution
The correct option is C123 EfEb=2031 (given). Also Ef−Eb=−33 (given) ..... (i) Substituting Eb=3120Ef, in equation (i) we get Ef−3120Ef=−33 or −1120Ef=−33 or Ef=33×2011=60kJmol−1 Eb=Ef+33=60+33=93kJmol−1 Thershold energy =Eb+PE of product =93+30=123kJmol−1