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Question

The threshold frequency for a certain metal is 3.3 × 1014 Hz. If light of frequency 8.2 × 1014 Hz is incident on the metal, predict the cutoff voltage for the photoelectric emission.

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Solution

Threshold frequency of the metal,

Frequency of light incident on the metal,

Charge on an electron, e = 1.6 × 10−19 C

Planck’s constant, h = 6.626 × 10−34 Js

Cut-off voltage for the photoelectric emission from the metal =

The equation for the cut-off energy is given as:

Therefore, the cut-off voltage for the photoelectric emission is


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