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Question

The threshold frequency for a certain photosensitive metal is ν0. When it is illuminated by light of frequency ν=2ν0, the maximum velocity of photoelectrons is v0. What will be the maximum velocity of the photoelectrons when the same metal is illuminated b a light of frequency ν=5ν0?

A
2v0
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B
2v0
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C
22v0
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D
4v0
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Solution

The correct option is B 2v0
We know that, 12mv2max=h(νν0)
For light of frequency ν=2ν0, we have 12mv20=h(2ν0ν0)=hν0 .....(i)
For light of frequency ν=5ν0, we have 12mv2=h(5ν0ν0)=4hν0 .....(ii)
Dividing (ii) by (i), v2=4v20
v=2v0
Hence, the correct choice is (b).

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