Question

The threshold wavelength for photoelectric effect of a metal is $6500\stackrel{\circ }{A}$. The work function of the metal is approximately

• A. 2 eV
• B. 1 eV
• C. 0.1eV
• D. 3 eV

Answer 1

The correct option is A

2 eV

${\lambda }_0=\frac{12375}{6500}=1.9eV\approx 2ev$