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Question

The threshold wavelength for tungsten is 272nm. A light of frequency 1.45×1015Hz is incident. Find the stopping potential.

A
1.37V
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B
1.47V
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C
1.57V
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D
1.51V
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Solution

The correct option is A 1.47V
Since the threshold wavelength is 272nm then the work function is -

ϕ=1240272=4.56eV;

Energy of the incident photon is-

hν=6.625×1034×1.45×10151.6×1019

=6.03eV
So the stopping potential is-
eVs=hνϕ or Vs=6.034.56=1.47V
So, the answer is option (B).

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